2x+(x-3)(x+4)=x^2

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Solution for 2x+(x-3)(x+4)=x^2 equation: 


Simplifying
2x + (x + -3)(x + 4) = x2

Reorder the terms:
2x + (-3 + x)(x + 4) = x2

Reorder the terms:
2x + (-3 + x)(4 + x) = x2

Multiply (-3 + x) * (4 + x)
2x + (-3(4 + x) + x(4 + x)) = x2
2x + ((4 * -3 + x * -3) + x(4 + x)) = x2
2x + ((-12 + -3x) + x(4 + x)) = x2
2x + (-12 + -3x + (4 * x + x * x)) = x2
2x + (-12 + -3x + (4x + x2)) = x2

Combine like terms: -3x + 4x = 1x
2x + (-12 + 1x + x2) = x2

Reorder the terms:
-12 + 2x + 1x + x2 = x2

Combine like terms: 2x + 1x = 3x
-12 + 3x + x2 = x2

Add '-1x2' to each side of the equation.
-12 + 3x + x2 + -1x2 = x2 + -1x2

Combine like terms: x2 + -1x2 = 0
-12 + 3x + 0 = x2 + -1x2
-12 + 3x = x2 + -1x2

Combine like terms: x2 + -1x2 = 0
-12 + 3x = 0

Solving
-12 + 3x = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '12' to each side of the equation.
-12 + 12 + 3x = 0 + 12

Combine like terms: -12 + 12 = 0
0 + 3x = 0 + 12
3x = 0 + 12

Combine like terms: 0 + 12 = 12
3x = 12

Divide each side by '3'.
x = 4

Simplifying
x = 4

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